2 puzzles from Richard von Mises, each explained in a minute and credited to the original work. Free on Savvy.
How many people do you need in a room before it's more likely than not that two of them share a birthday?
— Richard von Mises, Über Aufteilungs- und Besetzungswahrscheinlichkeiten (the classic 'birthday problem')
It sounds impossible: 23 people, out of 365 possible birthdays, yet the chance two of them share one already tips past 50%. The trick is that you're not checking one person against…
— Richard von Mises, Uber Aufteilungs- und Besetzungswahrscheinlichkeiten